x^2+1,7x-184,8=0

Solution for x^2+1,7x-184,8=0 equation:

x^2+1.7x-184.8=0

a = 1; b = 1.7; c = -184.8;
Δ = b2-4ac
Δ = 1.72-4·1·(-184.8)
Δ = 742.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.7)-\sqrt{742.09}}{2*1}=\frac{-1.7-\sqrt{742.09}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.7)+\sqrt{742.09}}{2*1}=\frac{-1.7+\sqrt{742.09}}{2}
$